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#103348: "Better algorithm in order to get less repeats"

inforequest: 開發者需要更詳細的建議內容

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2023年Nov7日 11:22 • cigma • 此建議尚未被開發者分析過:

2023年Nov7日 11:28 • KuWizard • 開發者需要更詳細的建議內容:

As I already mentioned in the thread mentioned, if there's any developer who would like to invest their time - I'm ready to share the code and lead to the correct direction.
Sorry for that but I'm not ready to invest my time in Just One anymore

2023年Nov7日 13:28 • Mr Karotte • 開發者需要更詳細的建議內容:

I'd be game to include changes. Still wondering whether it might not be easier to just add a couple hundred extra words.

2023年Nov7日 14:23 • KuWizard • 開發者需要更詳細的建議內容:

@Mr Karotte, It will be easier technically of course. But the publisher is against it.

2023年Nov7日 14:31 • Dorian Gray2 • 開發者需要更詳細的建議內容:

KuWizard: Like I Poster in the forum:
So for example, if $wordID is 1, it would take the first word for every 13 card?
That would be like 5 options for the card index combinations.

I guess the fix would be to use a different word index for every of the 13 cards. that would be like 5^13 = 1.220.703.125 options.

So, you would have to recalculate the wordID for each card, instead of computing it once on game start. Seems to be a pretty trivial change, isn't it?

If you would share code I could take a look at that.

2023年Nov7日 15:26 • KuWizard • 開發者需要更詳細的建議內容:

@Dorian Gray2, this is a trivial change indeed however I just don't get how double shuffling gets a better chance of getting a new word. I already shuffle "cards" so it's randomised. Randomising a number to get a word (choosing a random number from 0-4) looks like a unnecessary complication. But if you have a proof that this does increase randomness - I'll add this, no problem.

2023年Nov7日 15:46 • Dorian Gray2 • 開發者需要更詳細的建議內容:

Well, each wod should have the same likelihood. Im just talking about the number of game variation. It would still be good to make that change, as that would be closer to a real game behaviour.

I don't have an idea why this algo would be biased towards specific words. I guess that either your card shuffling or the index selection is flawed. Are you using random_int(4) for that wordID? And how do you shuffle cards?

2023年Nov7日 15:54 • KuWizard • 開發者需要更詳細的建議內容:

en.doc.boardgamearena.com/Main_game_logic:_yourgamename.game.php#Dice_and_bga_rand
We are forced to use bga_rand() and I'm using it.

However for cardIds I create an array from 0 to 549, use PHP shuffle() method and take first 13 or first 550 depending on a game option.

2023年Nov8日 13:00 • Dorian Gray2 • 開發者需要更詳細的建議內容:

KuWizard: Proof for less repetitions is as follows:

Consider two different games.
Assume you drew [b]two[/b] equal [b]cards[/b] in both games.
The propability that [b]both[/b] cards have the same word (two repetitions) is:
- 20 % in your variant (you have to select the same index in the second game as in the first, and both words will repeat)
- 4 % in the variant with indices per card (as you select a different index for each card).

If you have 3 same cards, it's always 20% in your variant, and 0.8% in the index-per-card-variant.

I guess that would just feel more random to players. If you have one repetition, you don't notice it. If you have [b]two[/b] repetitions, you might notice it.

So, could you pretty please change it? :)

2025年Apr19日 23:53 • eneri • 開發者需要更詳細的建議內容:

This is still an issue: We played three games today:
Game 1) with 4 players,
Game 2) new game with a 5th player joined
Game 3) rematch of game 2 with the same players.
In the 3rd game, we had 3 words that we already had in the first game.

@Dorian Gray2 or @Mr Karotte, did you have a chance to look at the code?
I would vote for option C: let the players pick one of the 5 words on the card - but this is probably the most complex change, as the game is developed with individual words, not with cards, isn't it? Or why would there be 500 cardIds (and not 110?) as mentioned here: "However for cardIds I create an array from 0 to 549, use PHP shuffle() method and take first 13 or first 550 depending on a game option."

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#103348: "Better algorithm in order to get less repeats"

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