#115287: "had to fight bandit twice"
這是關於哪方面的案件？
發生什麼事? 請從下方選擇
發生什麼事? 請從下方選擇
請檢查是否已有同課題案件
若肯定，請「投票」給這樁案件。最高票的案件將「優先」處理！
| # | Status | Votes | Game | Type | Title | Last update |
|---|
細節描述
-
• 如果可以的話，請轉貼螢幕顯示的錯誤訊息。
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
-
• 請說明你當時想做什麼，你做了什麼，然後發生了什麼事
at the end of the game when it killed us
• 你的瀏覽器是什麼？
Google Chrome v121
-
• 請簡明精確地解釋你的建議，以便讓人一目了然。
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
• 你的瀏覽器是什麼？
Google Chrome v121
-
• 當你不能動作時，螢幕上顯示什麼？（螢幕全黑？部份遊戲介面？錯誤訊息？）
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
• 你的瀏覽器是什麼？
Google Chrome v121
-
• 遊戲規則的哪部分在 BGA 版本有所錯漏？
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
-
• 這項違反規則之處可否在遊戲重播中看到？若可以是在哪步？（重播時左上角資訊）
at the end of the game when it killed us
• 你的瀏覽器是什麼？
Google Chrome v121
-
• 你當時想採取哪個遊戲行動？
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
-
• 你想觸發這個遊戲行動時做了什麼？
at the end of the game when it killed us
-
• 當你試著這麼做時發生了什麼（錯誤訊息、遊戲狀態條訊息...）？
• 你的瀏覽器是什麼？
Google Chrome v121
-
• 問題發生在遊戲的哪一步？（目前遊戲指示是什麼）
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
-
• 當你試著進行遊戲動作時發生了什麼（錯誤訊息、遊戲狀態條訊息...）？
at the end of the game when it killed us
• 你的瀏覽器是什麼？
Google Chrome v121
-
• 請描述顯示問題。 建議將此錯誤的螢幕截圖上傳到 Imgur.com 並轉貼連結。
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
• 你的瀏覽器是什麼？
Google Chrome v121
-
• 請簡明精確地解釋你的建議，以便讓人一目了然。
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
• 你的瀏覽器是什麼？
Google Chrome v121
案件沿革
Move 89: Clutron started the Bandit card
Move 90: Clutron decided to attack the Bandit rather than bribe him
...
Move 97: Bandit is defeated
[At this point, Clutron's turn is done, but runescience hasn't encountered a card yet]
Move 98: runescience starts the Bandit card
Move 99: runescience also decided not to bribe the Bandit.
I'm not sure there's a bug here.
Both players need to encounter all non-monster cards and the bandit is not a monster. If a monster results from an encounter, both players will fight the monster together, but it doesn't end the encounter for the player who hasn't gone yet.
For example, the rules are explicit that both players encounter a trap. Whether the first player succeeds or fails, the second player will also encounter the same trap. Even if the first player rolls the dungeon die such that they fight a monster, the other player must still encounter the trap and may roll that same monster die again.
It works this way for all non-monster cards. The Bandit isn't a monster card; it's a different sort of encounter where a decision is made. You both made decisions that resulted in combats.
From the rules, you got no mention of the bandit, so:
- if you consider the bandit is not a monster, then you got no indication of what you should do with it. Since it's not writed on the rules, I don't see why you couldn't just ignore the bandit on that case? It's a card without effect (I'm trolling here, but that's my main point)
- if you consider the bandit is a monster, then the rules makes sense to me, and so "It is a fight to the death, and whoever loses all their HP dies horribly", so the bandit dies. So I would assume that bandit is discarded or has no effect anymore
From the forum post, it's a question about what if one player pay the toll and the other one don't. It's not what is present here (or on that game: boardgamearena.com/archive/replay/240320-1000/?table=496542833&player=84207926&comments=84207926;# floor 3 i think ).
So what I would propose is the following:
- first player can choose to pay the toll or not:
if he does not goes to fight section
if he does, then the second player can choose to pay the toll or not. If he does not, goes to fight section. If he does, end the event for both players
Fight section: disable the toll option, and make everyone restart the card they are on. Which mean anyone can choose who will fight the bandit first. Once he is defeated end the card.
I don't think you should ever have two fights on a row from a single bandit card.
> if you consider the bandit is not a monster, then
> you got no indication of what you should do with it
This is untrue. The rules definitely cover how non-monsters are encountered by two players. Both player must encounter all non-monster cards separately. For example, traps are encountered by both players separately, even if the trap results in both players needing to face a monster. Bandit works like that, too.
Then it's double monster, which makes it a very horrible card.
It makes no sense to me...
As I'm not interested in debating this, I'll kindly refer you to the forums if you wish to discuss it further, especially since this report is already a dupliciate of another false report.
為本案件添加內容
- 其他同樣狀況的桌號／步數
- 按 F5 是否解決了這個問題？
- 問題是否發生了好幾次？每次都發生？時好時壞？
- 建議將此錯誤的螢幕截圖上傳到 Imgur.com 並轉貼連結。
