所有案件
巫術學院 的案件
#17195: "Issue selecting a marble"
fixed: 錯誤已修復
1
這是關於哪方面的案件？
發生什麼事? 請從下方選擇
遊戲介面阻擋我行使某些規則所允許的操作
細節描述
-
• 你當時想採取哪個遊戲行動？
take a marble
-
• 你想觸發這個遊戲行動時做了什麼？
click on the marble
-
• 當你試著這麼做時發生了什麼（錯誤訊息、遊戲狀態條訊息...）？
nothing
• 你的瀏覽器是什麼？
Google Chrome v81
案件沿革
2020年 5月11日 8:33 • Jer3my • 開發者尚未重現這項錯誤:
Hey Adam,
I found a rather odd thing happen. at the table the issue happened at move 105. I began by taking a marble for "a little help", after which I wanted to select the marble that had most recently rolled into the active area, but the interface wouldn't let me choose this newly available marble. Checking other rows I found I could choose the upper most marble in each other row. I'm guessing this has something to do with the system remembering that that marble wasn't available and not updating that the marble should now have become available.
Strangely, I was able to remedy the problem. After a refresh of my browser, I was then able to select the uppermost marble in the column I wanted (column 4).
Cheers!
Jeremy
I found a rather odd thing happen. at the table the issue happened at move 105. I began by taking a marble for "a little help", after which I wanted to select the marble that had most recently rolled into the active area, but the interface wouldn't let me choose this newly available marble. Checking other rows I found I could choose the upper most marble in each other row. I'm guessing this has something to do with the system remembering that that marble wasn't available and not updating that the marble should now have become available.
Strangely, I was able to remedy the problem. After a refresh of my browser, I was then able to select the uppermost marble in the column I wanted (column 4).
Cheers!
Jeremy
2020年 5月11日 12:38 • apollo1001 • 開發者已確認這項錯誤:
Thanks Jeremy - I’ve just tried this and was able to reproduce. Ion busy most of today but might be able to patch this evening. Adam
為本案件添加內容
任何可能重現這項錯誤或了解你的建議之相關資訊，都請在此填寫:
- 其他同樣狀況的桌號／步數
- 按 F5 是否解決了這個問題？
- 問題是否發生了好幾次？每次都發生？時好時壞？
- 建議將此錯誤的螢幕截圖上傳到 Imgur.com 並轉貼連結。
