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{THIS_GAME_BUGS}
#18199: "Swiss tournament pairing improvement: color selection (hive, chess)"
#18199: "Swiss tournament pairing improvement: color selection (hive, chess)"
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建議:依我所見,下列調整將大幅改善此站
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建議:依我所見,下列調整將大幅改善此站
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# | Status | Votes | Game | Type | Title | Last update |
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細節描述
• 如果可以的話,請轉貼螢幕顯示的錯誤訊息。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 請說明你當時想做什麼,你做了什麼,然後發生了什麼事
• 你的瀏覽器是什麼?
Google Chrome v81
• 請轉貼未翻譯的英文字句。 建議將此錯誤的螢幕截圖上傳到 Imgur.com 並轉貼連結。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 這些文字存在於 翻譯系統 中嗎?若為真,其是否已被翻譯超過 24 小時?
• 你的瀏覽器是什麼?
Google Chrome v81
• 請簡明精確地解釋你的建議,以便讓人一目了然。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 你的瀏覽器是什麼?
Google Chrome v81
• 當你不能動作時,螢幕上顯示什麼?(螢幕全黑?部份遊戲介面?錯誤訊息?)
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 你的瀏覽器是什麼?
Google Chrome v81
• 遊戲規則的哪部分在 BGA 版本有所錯漏?
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 這項違反規則之處可否在遊戲重播中看到?若可以是在哪步?(重播時左上角資訊)
• 你的瀏覽器是什麼?
Google Chrome v81
• 你當時想採取哪個遊戲行動?
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 你想觸發這個遊戲行動時做了什麼?
• 當你試著這麼做時發生了什麼(錯誤訊息、遊戲狀態條訊息...)?
• 你的瀏覽器是什麼?
Google Chrome v81
• 問題發生在遊戲的哪一步?(當前遊戲指示是什麼)
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 當你試著進行遊戲動作時發生了什麼(錯誤訊息、遊戲狀態條訊息...)?
• 你的瀏覽器是什麼?
Google Chrome v81
• 請描述顯示問題。 建議將此錯誤的螢幕截圖上傳到 Imgur.com 並轉貼連結。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 你的瀏覽器是什麼?
Google Chrome v81
• 請轉貼未翻譯的英文字句。 建議將此錯誤的螢幕截圖上傳到 Imgur.com 並轉貼連結。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 這些文字存在於 翻譯系統 中嗎?若為真,其是否已被翻譯超過 24 小時?
• 你的瀏覽器是什麼?
Google Chrome v81
• 請簡明精確地解釋你的建議,以便讓人一目了然。
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• 你的瀏覽器是什麼?
Google Chrome v81
案件沿革
2020年 5月27日 20:05 • csigeee • 此建議尚未被開發者分析過:
In this tournament I played 5-times with black and only once with white:
boardgamearena.com/tournament?id=38119
boardgamearena.com/tournament?id=38119
2020年 6月17日 10:07 • junibegood • 此建議尚未被開發者分析過:
This could probably be generalized to any game with a turn order. Pairing should try to balance the number of games you play as first player / second player (or more if there is more than 2 players per game) and avoid playing at the same spot more than two times in a row.
2021年11月11日 8:03 • stepanzo • 此建議尚未被開發者分析過:
This is not only from Swiss system, but for Round Robins too.
For example, in this tournament Frasco has all 4 games as white and pcapella has all 4 games black boardgamearena.com/tournament?id=106569
For example, in this tournament Frasco has all 4 games as white and pcapella has all 4 games black boardgamearena.com/tournament?id=106569
2022年11月 4日 5:23 • Mathew5000 • 此建議尚未被開發者分析過:
Related (or duplicate) reports:
boardgamearena.com/bug?id=32483
boardgamearena.com/bug?id=32713
boardgamearena.com/bug?id=72619
boardgamearena.com/bug?id=32483
boardgamearena.com/bug?id=32713
boardgamearena.com/bug?id=72619
為本案件添加內容
任何可能重現這項錯誤或了解你的建議之相關資訊,都請在此填寫:
- 其他同樣狀況的桌號/步數
- 按 F5 是否解決了這個問題?
- 問題是否發生了好幾次?每次都發生?時好時壞?
- 建議將此錯誤的螢幕截圖上傳到 Imgur.com 並轉貼連結。
更改案件狀態為:
bug?id=18199