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Off the Rails 的案件
#22021: "wrong tie break"
notabug: 這並非程式錯誤
1
這是關於哪方面的案件？
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規則：遊戲規則有所錯漏
細節描述
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• 遊戲規則的哪部分在 BGA 版本有所錯漏？
WRONG: most jewels in stockpile (x100), followed by most precious jewels in stockpile (x1)
CORRECT: most Jewels in their Stockpile is the winner. If there is still no winner, the player with the least number of Rocks in their Stockpile wins.
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• 這項違反規則之處可否在遊戲重播中看到？若可以是在哪步？（重播時左上角資訊）
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• 你的瀏覽器是什麼？
Google Chrome v84
案件沿革
2020年Aug2日 06:40 • sarasa1a • 開發者尚未重現這項錯誤:
It may be BGA original rule, but I will report it because it is not listed anywhere.
2020年Aug2日 08:14 • paramesis • 這並非程式錯誤:
Thank you for your concern. This an accurate way to numerically represent both tiebreakers as intended by the designer as a single comparable number, which BGA requires. The rulebook states that rocks are considered "Jewels" for all rules other than the one that you must pick up rocks first (page 5).
Counting rocks as a minimum value is equivalent to counting non-rocks as a maximum value. Each rock is counted as 100 in tiebreaker, and each Precious (non-rock) Jewel is counted as 101. In the table linked to this report, twes stockpiled 13 Jewels, including 4 Rocks and 9 Precious Jewels, for a tiebreaker score of 1309. CK99 stockpiled 9 Jewels, including 1 Rock and 8 Precious Jewels, for a tiebreaker score of 908. twes won the first tiebreaker, so the second tiebreaker had no impact. If they had both collected the same number of Jewels, then the higher number of non-rocks (equivalent to "the player with the least number of Rocks") would win the tiebreaker.
The text of the tiebreaker explanation on BGA does not necessarily need to match the rulebook verbatim. Consider Kingdomino, where the first edition rulebook states:
"In case of a tie, the player with the biggest territory (with the highest number of squares) wins the game. If it is still a tie, the player who has the most crowns wins the game." In BGA this is implemented as: "Tie breaker: Size of the biggest territory (x100), then total number of crowns (x1)"
Counting rocks as a minimum value is equivalent to counting non-rocks as a maximum value. Each rock is counted as 100 in tiebreaker, and each Precious (non-rock) Jewel is counted as 101. In the table linked to this report, twes stockpiled 13 Jewels, including 4 Rocks and 9 Precious Jewels, for a tiebreaker score of 1309. CK99 stockpiled 9 Jewels, including 1 Rock and 8 Precious Jewels, for a tiebreaker score of 908. twes won the first tiebreaker, so the second tiebreaker had no impact. If they had both collected the same number of Jewels, then the higher number of non-rocks (equivalent to "the player with the least number of Rocks") would win the tiebreaker.
The text of the tiebreaker explanation on BGA does not necessarily need to match the rulebook verbatim. Consider Kingdomino, where the first edition rulebook states:
"In case of a tie, the player with the biggest territory (with the highest number of squares) wins the game. If it is still a tie, the player who has the most crowns wins the game." In BGA this is implemented as: "Tie breaker: Size of the biggest territory (x100), then total number of crowns (x1)"
2020年Aug3日 05:54 • paramesis • 這並非程式錯誤:
I updated the tiebreaker description to "most jewels in stockpile (x100), then fewest rocks in stockpile (+1 for each non-rock jewel)" to clarify how the tiebreaker implements the written rules. I can see how the previous description would be ambiguous, as the distinction "precious jewels" is only referenced on one of the mission cards.
為本案件添加內容
任何可能重現這項錯誤或了解你的建議之相關資訊，都請在此填寫:
- 其他同樣狀況的桌號／步數
- 按 F5 是否解決了這個問題？
- 問題是否發生了好幾次？每次都發生？時好時壞？
- 建議將此錯誤的螢幕截圖上傳到 Imgur.com 並轉貼連結。
